(4x^2-3x-1)/(10+7x)=0

Solution for (4x^2-3x-1)/(10+7x)=0 equation:

(4x^2-3x-1)/(10+7x)=0


Domain of the equation: (10+7x)!=0

We move all terms containing x to the left, all other terms to the right

7x!=-10

x!=-10/7

x!=-1+3/7

x∈R


We add all the numbers together, and all the variables

(4x^2-3x-1)/(7x+10)=0

We multiply all the terms by the denominator


(4x^2-3x-1)=0

We get rid of parentheses

4x^2-3x-1=0

a = 4; b = -3; c = -1;
Δ = b2-4ac
Δ = -32-4·4·(-1)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-5}{2*4}=\frac{-2}{8}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+5}{2*4}=\frac{8}{8}
=1
$